SHMHard
Question
The bob of a single pendulum is a spherical hollow ball filled with water. A piugged hole near the bottom of the oscillating bob geys suddenly unolugged. During observation, till water is coming out, the time period of oscillation would
Options
A.first decrease and then increase to the original value
B.first increase and then decrease to the original value
C.increase towerds a satugration value
D.remain unchanged
Solution
Centre of mass of combination of liquid and hollow portion (at position l), first goes down (to l = ᐃl)and when total water is drained out, centre of mass regain its original position (to l),
T = 2π
∴ ′T′ first increse and then decrease to original value.
T = 2π
∴ ′T′ first increse and then decrease to original value.
Create a free account to view solution
View Solution FreeMore SHM Questions
The position of a particle at time t moving in x-y plane is given by = (î + 2ĵ) A cos ωt. Then, the motio...The energy at the mean position of a pendulum will be :...The graph shows the variation of displacement of a particle executing S.H.M with time We inference from this graph that ...Two blocks masses 3 kg and kg rest on a horizontal smooth surface . The 3 kg block is attached to a spring with a force ...The magnitude of average acceleration in half time period in a simple harmonic motion is...