Rotational MotionMedium

Question

Thane quarter sector is cut from a uniform circular disc of radius R. This sector has mass M. It is made to rotate about a line perpendicular to its plane and passing through the centre of the original disc. It moment of inrrtia about the axis of rotation is

Options

A.mR2
B.mR2
C.mR2
D.√2mR2

Solution

For complete disc with mass ′4M′, M.l. about given axis = (4M) (R2/2) = 2MR2
Hence, by symmetry for the given quarter of the disc
M.I. = 2MR2/4 = MR2

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