Basic Maths and Units and DimensionsHard
Question
Thane quarter sector is cut from a uniform circular disc of radius R. This sector has mass M. It is made to rotate about a line perpendicular to its plane and passing through the centre of the original disc. It moment of inrrtia about the axis of rotation is
Options
A.
mR2
mR2B.
mR2
mR2C.
mR2
mR2D.√2mR2
Solution
For complete disc with mass ′4M′, M.l. about given axis = (4M) (R2/2) = 2MR2
Hence, by symmetry for the given quarter of the disc
M.I. = 2MR2/4 =
MR2
Hence, by symmetry for the given quarter of the disc
M.I. = 2MR2/4 =
MR2Create a free account to view solution
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