Chemical BondingEasy
Question
The number of σ - and π -bonds present in pent-4-en-l-yne is
Options
A.10, 3
B.4, 9
C.3, 10
D.9, 4
Solution
HC ≡ C - CH2 - CH = CH2
pent-4-en-1-yne
Triple bond between C and C contains one σ bond and one π bond.
Total σ bonds = 10
Total π bond = 3
pent-4-en-1-yne
Triple bond between C and C contains one σ bond and one π bond.
Total σ bonds = 10
Total π bond = 3
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