AIPMT | 2014Organisms and PopulationHard
Question
In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is
Options
A.0.4
B.0.5
C.0.6
D.0.7
Solution
According to Hardy Weinberg principle.
p2 + 2pq + q2 = 1; (p + q)2 = 1
(AA) p2 = 360 out of 1000 individual or p2 = 36 out of 100
q2 = 160 out of 1000 or q2 = 16 out of 100
so q =
= .4. As p + q = 1
so, p is 0.6.
p2 + 2pq + q2 = 1; (p + q)2 = 1
(AA) p2 = 360 out of 1000 individual or p2 = 36 out of 100
q2 = 160 out of 1000 or q2 = 16 out of 100
so q =
= .4. As p + q = 1 so, p is 0.6.
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