A man whose father was colour blind marries a woman who had a colour blind mother and normal father.

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A man whose father was colour blind marries a woman who had a colour blind mother and normal father. What percentage of male children of this couple will be colour blind?

Accepted Answer

∴ Colourblind male = 50% (c) [Key Concept: X-linked Colour Blindness — Carrier Mother] Man's father was colour blind (X^c Y) → man received Y from father, X from mother (normal) → man is X^C Y (normal vision, cannot be carrier). Woman's mother was colour blind (X^c X^c) → woman received X^c from mother, X^C from father → woman is X^C X^c (carrier). Cross: X^C Y (man) × X^C X^c (woman) → sons: X^C Y (50% normal) or X^c Y (50% colour blind). Therefore 50% of male children will be colour blind. Answer: (c) 50%.

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