AIPMT | 2014Alternating CurrentMedium
Question
A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6A, the voltage across thesecondary coil and the current in the primary coil respectively are
Options
A.300 V, 15 A
B.450 V, 15 A
C.450 V, 13.5 A
D.600 V, 15 A
Solution
Power ouput = 3kW ×
= 2.7 kW
Ib = 6A
Vs =
= 450 V
Ip =
= 15 A
= 2.7 kWIb = 6A
Vs =
= 450 VIp =
= 15 A Create a free account to view solution
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