JEE Advanced | 2014Differential EquationMedium
Question
The function y = f(x) is the solution of the differential equation 
in (- 1, 1) satisfying f(0) = 0. Then 
f(x) dx is
in (- 1, 1) satisfying f(0) = 0. Then f(x) dx isOptions
A.
B.
C.
D.
Solution
I.F. =
So, y
= 
(x4 + 2x)dx = 
+ x2 + c Given f(0) = 0 ⇒ c = 0
So y =
= f(x)I =
f(x)dx = 
dx = 2 
Let x = sinθ
I = 2
sin2 θdθ = (1 - cos2θ)dθ=
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