JEE Advanced | 2014Differential EquationHard

Question

The function y = f(x) is the solution of the differential equation in (- 1, 1) satisfying f(0) = 0. Then f(x) dx is

Options

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Solution


I.F. =
So, y = (x4 + 2x)dx = + x2 + c
Given f(0) = 0 ⇒ c = 0
So y == f(x)
I = f(x)dx = dx = 2
Let x = sinθ
I = 2 sin2 θdθ = (1 - cos2θ)dθ
=

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