JEE Advanced | 2014Differential EquationHard

Question

The function y = f(x) is the solution of the differential equation in (- 1, 1) satisfying f(0) = 0. Then f(x) dx is

Options

A.
B.
C.
D.

Solution


I.F. =
So, y = (x4 + 2x)dx = + x2 + c
Given f(0) = 0 ⇒ c = 0
So y == f(x)
I = f(x)dx = dx = 2
Let x = sinθ
I = 2 sin2 θdθ = (1 - cos2θ)dθ
=

Create a free account to view solution

View Solution Free
Topic: Differential Equation·Practice all Differential Equation questions

More Differential Equation Questions

The solution of the equation = 0 is-...The differential equation for the line y = mx + c is ( where c is arbitrary constant)-...The solution of = 0, is -...The solution the differential equation (ex + e-x) + 1 = 0 is are -...The solution of (x)dx + (y)dy = 0 is -...