JEE Advanced | 2014ProbabilityHard
Question
Three boys and two girls stand in a queue. The probability, that the number of boys ahead of every girl is at least one more than the number of girls ahead of her, is
Options
A.
B.
C.
D.
Solution
Case I : 
2 × 4! = 48
Case II :
n(E) = 60
P(E) =
2 × 4! = 48
Case II :
n(E) = 60
P(E) =
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