JEE Advanced | 2014d and f-Block ElementsMedium
Question
The pair(s) of reagents that yield paramagnetic species is/are
Options
A.Na and excess of NH3
B.K and excess of O2
C.Cu and dilute HNO3
D.O2 and 2-ethylanthraquinol
Solution
K + O2 → KO2
(excess)
O2- is paramagnetic due to unpaired electron in antibonding orbital
3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
(diluted)
NO is paramagnetic due to unpaired electrons on ″N″
(excess)
O2- is paramagnetic due to unpaired electron in antibonding orbital
3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
(diluted)
NO is paramagnetic due to unpaired electrons on ″N″
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