JEE Advanced | 2014d and f-Block ElementsHard
Question
The pair(s) of reagents that yield paramagnetic species is/are
Options
A.Na and excess of NH3
B.K and excess of O2
C.Cu and dilute HNO3
D.O2 and 2-ethylanthraquinol
Solution
K + O2 → KO2
(excess)
O2- is paramagnetic due to unpaired electron in antibonding orbital
3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
(diluted)
NO is paramagnetic due to unpaired electrons on ″N″
(excess)
O2- is paramagnetic due to unpaired electron in antibonding orbital
3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
(diluted)
NO is paramagnetic due to unpaired electrons on ″N″
Create a free account to view solution
View Solution FreeMore d and f-Block Elements Questions
Given below are two statements :Statement I: The number of pairs, from the following, in which both the ions are coloure...The color of KMnO4 is due to :...What is the correct order of spin only magnetic moment of Mn2+, Cr2+ and V2+ :-...A first row transition metal (M) does not liberate $H_{2}$ gas from dilute HCl .1 mol of aqueous solution of ${MSO}_{4}$...In context with the transition elements, which of the following statements is incorrect ?...