SemiconductorHard
Question
The input resistance of a common emitter transistor amplifier, if the output resistance is 500k, the current gain α = 0.98 and power gain is 6.0625 × 106, is
Options
A.198 Ω
B.300 Ω
C.100 Ω
D.400 Ω
Solution
R0 = 500 k
Power gain = 6.0625 × 106
we have ,voltage gain Av = β
But current gain,
β =
= 49
∴ Av = 49 ×
Given 6.0625 × 106 = Av × β
=
× 49
or Ri =
= 198Ω
Power gain = 6.0625 × 106
we have ,voltage gain Av = β
But current gain,
β =
= 49∴ Av = 49 ×
Given 6.0625 × 106 = Av × β
=
× 49or Ri =
= 198Ω Create a free account to view solution
View Solution FreeMore Semiconductor Questions
When two semiconductor of p and n type are brought in to contact, they form a p-n junction which acts like a : -...To use transistor as an amplifier :–...In L-C oscillator amplifier which feed back is used...The energy band diagrams for three semiconductor samples of silicon are as shown. We can then assert that :-...When value of current increases in p-n junction, then the value of contact potential : -...