SemiconductorMedium
Question
A Ge specimen is doped with Al. The concentration of acceptor atoms is ~ 1021 atoms/m3. Given that the intrinsic concentration of electron -hole pairs is ~1019/m3,the concentration of electrons in the specimen is
Options
A.1017 / m3
B.1015 / m3
C.104 / m3
D.102 / m3
Solution
ne nh = ni2
ne is concentration of electron, nh is concentration of hole and ni is concentration of electron, holes pairs in intrinsic semi-conductor.
Here nh = 1021, ne = ?, ni = 1019
1021 × ne = 1019 × 1019
ne =
× 1017 m-3
ne is concentration of electron, nh is concentration of hole and ni is concentration of electron, holes pairs in intrinsic semi-conductor.
Here nh = 1021, ne = ?, ni = 1019
1021 × ne = 1019 × 1019
ne =
× 1017 m-3 Create a free account to view solution
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