ElectroMagnetic InductionHard
Question
With decrease of current in the primary coil from 2 amperes to to zero value in 0.01 s the emf generated in the secondary coil is 1000 volts. The mutual inductance of the two coils is
Options
A.1.25 H
B.2.50 H
C.5.00 H
D.10.00 H
Solution
The emf induced in secondary is given by e = 
⇒ 1000 = M 
(since cuurent is reduced dI = - ve)
M =
= 5.00H
⇒ 1000 = M (since cuurent is reduced dI = - ve)
M =
= 5.00HCreate a free account to view solution
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