Magnetic field due to currentHard
Question
A magnet 10 cm long and having a pole strength 2 amp m is deflected through 30o from the magnetic meridian. The horizontal component of earth′s induction is 0.32 × 10-4 tesla then the value of deflecting couple is :
Options
A.32 × 10-7 Nm
B.16 × 10-7 Nm
C.64 × 10-7 Nm
D.48 × 10-7 Nm
Solution
M = 2 × 
= 0.2
Value of restoring couple = MH sin φ
= 0.2 × 0.32 × 10-4 sin 30o
= 0.2 × 0.32 × 10-4 ×
= 32 × 10-7 Nm
= 0.2Value of restoring couple = MH sin φ
= 0.2 × 0.32 × 10-4 sin 30o
= 0.2 × 0.32 × 10-4 ×
= 32 × 10-7 NmCreate a free account to view solution
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