ElectroMagnetic InductionHard
Question
An electron beam passes through a magnetic field of 2 × 10-3 Wb/m2 and an electric field of 1.0 × 104 V/mboth acting simultaneously. The path electron remains undeviated. the speed of electron if the electric field is removed, And the radius of electron path will be respectively
Options
A.10 × 106 m/s,2.43 cm
B.2.5 × 106 m/s,0.43 cm
C.5 × 106 m/s,1.43 cm
D.none of these
Solution
B = 2 × 10-3 Wb/m2
E = 1 × 104V/m2
Since the path of election remains undeviated, qvb = qe or
v =
= 0.5 × 104
= 5 × 106 m/s
If the electricfield is removed, the pathof the charged particle is circular and magnetic field provides the necessary centripetal force. i.e.,
= Bev ⇒ r = 
E = 1 × 104V/m2
Since the path of election remains undeviated, qvb = qe or
v =
= 0.5 × 104= 5 × 106 m/s
If the electricfield is removed, the pathof the charged particle is circular and magnetic field provides the necessary centripetal force. i.e.,
= Bev ⇒ r = Create a free account to view solution
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