Current Electricity and Electrical InstrumentHard

Question

A wire of radius r has resistance R. If it is stretched to a radius , its resistance will be :

Options

A.16 R
B.2 R
C.4 R
D.zero

Solution

Let length & cross sectional area of wire be l &a respectively. ρ br the specific resistance, then
R = ρ
If radius becomes half, area becomes th or cross sectional area after4 the stretch .
Let its legth increases to l′. Since volume remains the same in the process,
l a = l′ × l′ = 4l
Let R′ be the resistance of streched wire
R′ = ρ × = 16 × ρ 16 R

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