Current Electricity and Electrical InstrumentHard
Question
A wire of radius r has resistance R. If it is stretched to a radius
, its resistance will be :
, its resistance will be :Options
A.16 R
B.2 R
C.4 R
D.zero
Solution
Let length & cross sectional area of wire be l &a respectively. ρ br the specific resistance, then
R = ρ
If radius becomes half, area becomes
th or cross sectional area after4 the stretch
.
Let its legth increases to l′. Since volume remains the same in the process,
l a = l′ ×
⇒ l′ = 4l
Let R′ be the resistance of streched wire
R′ = ρ ×
= 16 × ρ
16 R
R = ρ

If radius becomes half, area becomes
th or cross sectional area after4 the stretch
.Let its legth increases to l′. Since volume remains the same in the process,
l a = l′ ×
⇒ l′ = 4l Let R′ be the resistance of streched wire
R′ = ρ ×
= 16 × ρ
16 RCreate a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10Ω. The internal resistan...Two resistors of $100\Omega$ each are connected in series with a 9 V battery. A voltmeter of $400\Omega$ resistance is c...In the following circuit if VA−VB = 4V, then the value of resistance X in ohms will be : -...R = ⇒ R ∝ L2The equivalent resistance between the points A and B is -...The length of a potentiometer wire is 10m. A standard cell of 1.1 volt is balanced at 550cm length of the wire. The maxi...