ElectrostaticsHard
Question
The potential at a point p due to an electric dipole is 1.8 × 105V. If p is at distance of 50 cm apart from the centre 0 of the positive side of the axial line of the diple, what is the moment of the dipole?
Options
A.10 C-m
B.10-3 C-m
C.10-4 C-m
D.10-5 C-m
Solution
V = 
Fence, V = 1.8 × 105V, θ = 60o,
r = 50 × 10-2 = 0.5 m
∴ 1.8 × 105 = 9 × 109 ×
or P =
= 10-5C - m
Fence, V = 1.8 × 105V, θ = 60o,
r = 50 × 10-2 = 0.5 m
∴ 1.8 × 105 = 9 × 109 ×
or P =
= 10-5C - mCreate a free account to view solution
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