ElectrostaticsHard
Question
The potential at a point p due to an electric dipole is 1.8 × 105V. If p is at distance of 50 cm apart from the centre 0 of the positive side of the axial line of the diple, what is the moment of the dipole?
Options
A.10 C-m
B.10-3 C-m
C.10-4 C-m
D.10-5 C-m
Solution
V = 
Fence, V = 1.8 × 105V, θ = 60o,
r = 50 × 10-2 = 0.5 m
∴ 1.8 × 105 = 9 × 109 ×
or P =
= 10-5C - m
Fence, V = 1.8 × 105V, θ = 60o,
r = 50 × 10-2 = 0.5 m
∴ 1.8 × 105 = 9 × 109 ×
or P =
= 10-5C - mCreate a free account to view solution
View Solution FreeMore Electrostatics Questions
An elliptical cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. Th...A charge Q is placed at a distance of 4R above the centre of a disc of radius R. The magnitude of flux through the disc ...An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. ...The linear charge density on upper half of a segment of ring is λ and at lower half, it is − λ. The dire...An elementary particle of mass m and charge +e is projected with velocity v at a much more massive particle of charge Ze...