ElectrostaticsHard
Question
Charger q is uniformly distributed over a thin half ring of radius R. The electric field at the centre of the ring is
Options
A.
B.
C.
D.
Solution
From figure, d l = Rdθ
Charge on d l = λRd
where λ = linear charge density Electric field at centre due to dl
dE = k
We need to nconsider only the component dE cos θ, as the component dE sin θ will cancel out.
∴ Total field at centre = 2
dE cos θ
cos θ dθ 
(since λ = 
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