ElectrostaticsMedium
Question
Charger q is uniformly distributed over a thin half ring of radius R. The electric field at the centre of the ring is
Options
A.

B.

C.

D.

Solution

From figure, d l = Rdθ
Charge on d l = λRd
where λ = linear charge density Electric field at centre due to dl
dE = k

We need to nconsider only the component dE cos θ, as the component dE sin θ will cancel out.
∴ Total field at centre = 2
dE cos θ
cos θ dθ
(since λ =
)Create a free account to view solution
View Solution FreeMore Electrostatics Questions
Three charges of 0.1C each are placed on the corners of an equilateral triangle of side 1.0m. If the energy is supplied ...Four charges +Q, −Q, +Q and −Q are situated on the corners of a square then at the centre of square...Two spheres of radii R1 and R2 joined by a fine wire are raised to potential V. Let the surface charge densities at thes...Consider a uniform spherical distirbution of radius R1 centred at the origin O. In this distribution, a spherical cavity...A charge + q is fixed at each of the points x = x0, x = 3x0, x = 5x0 ...... ∞ on the x-axis and charge - q is fixe...