ThermodynamicsHard
Question
At what temperature the molecules of nitrogen will have the same rms velocity as the molecules of oxygen at 127oC
Options
A.457oC
B.273oC
C.350oC
D.77oC
Solution
Rms velocity of gas is
Vrms = 1.73
M = molecular mass
For oxygen,M = 16 × 2,
T = 127oC = 127 + 273 = 400 K
For nitrogen, M = 17 × 2, T = ?
⇒ 1.73
= 1.73 
⇒
⇒
⇒ TN2 =
× 400 = 350K
TN2 = 350K - 273K = 77o C
Vrms = 1.73
M = molecular mass
For oxygen,M = 16 × 2,
T = 127oC = 127 + 273 = 400 K
For nitrogen, M = 17 × 2, T = ?
⇒ 1.73
= 1.73 ⇒
⇒
⇒ TN2 =
× 400 = 350KTN2 = 350K - 273K = 77o C
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