Wave OpticsHardBloom L3
Question
Light of wavelength 589.3 nm is incident normally on a slit of width 0.01mm. The angular width of the central diffraction maximum at a distance of 1m from the slit, its:
Options
A.0.68o
B.0.34o
C.2.05o
D.none of these
Solution
In case of diffraction,
Angular width of central fringe =
= 2 × 589.3 × 10-4
= 1178.6 × 10-5 rad.
= 1178.6 × 10-5 ×
= 67563 × 10-5
= 0.68o
Angular width of central fringe =
= 2 × 589.3 × 10-4= 1178.6 × 10-5 rad.
= 1178.6 × 10-5 ×
= 67563 × 10-5= 0.68o
Create a free account to view solution
View Solution FreeMore Wave Optics Questions
A lift is desending with an acceleration 2 m/sec2. What will be the aparent weight of a person of 80 kg mass ?...In Young′s experiment, one slit is covered with a blue filter and the other (slit) with a yellow filter. Then the ...When abeam of light is used to determine the position of an object, the maximumaccueacy achieved if the light is :...Light waves travels not strictly in straight line, can be best explained by :Light waves travels not strictly in straigh...If rn is radius of nth half period zone, λ is wavelength, then area of nth half period zone of plane wavefront will...