Wave OpticsHard
Question
An astronomical telescope of fold angular magnification has a length of 44 cm the focal length of the objective is :
Options
A.44 cm
B.440 cm
C.40 cm
D.4 cm
Solution
In case of telescope,in normal adjustment,
m =
= 10
and fo + fe length of tube = 44
fo = 10 fe 10fe + fe = 44 ⇒ fe = 4
fo = 10 × 4 = 40cm
m =
= 10and fo + fe length of tube = 44
fo = 10 fe 10fe + fe = 44 ⇒ fe = 4
fo = 10 × 4 = 40cm
Create a free account to view solution
View Solution FreeMore Wave Optics Questions
A machine gun fires bullets of 50 gm at the speed of 1000 m/sec. If an average force of 200 N is exerted on the gun, the...In an interference pattern of two waves fringe width is β . If the frequency of source is doubled then fringe width...In a YDSE merriment two slits S1 and S2 have separation of d = 2 mm. The distance of the screen is D = m. Source S stars...A leaf which contains only green pigments, is illuminated by a laser of wavelength 0.6328 μm. It wound appear to be...The resultant amplitude in interference with two coherent sources depends upon :...