SHMMedium
Question
If A is the area of cross-section of a spring L is its length E is the Young′s modulus of the material of the spring then time period and force constant of the spring will be respectively:
Options
A.T = 2π 
B.
C.
D.T = 2π 
Solution
According to the formnula of young′s modulus
E =
where ᐃL is hte the extension in the spring
F =
Now, According to Hooke′s law
F = kᐃL
where k is the spring constantBy comparing(1)and (2)
KᐃL =
k =
time period, T = 2π
= 2π
E =
where ᐃL is hte the extension in the spring
F =
Now, According to Hooke′s law
F = kᐃL
where k is the spring constantBy comparing(1)and (2)
KᐃL =
k =
time period, T = 2π
= 2π
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