SHMMedium
Question
A coin is placed on a horizontal platform which undergoes vertical simple harmonic motion of angular frequency ω. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time
Options
A.at the mean position of the platform
B.for an amplitude of 
C.for an amplitude of 
D.at the highest position of the platform
Solution
For block A to move in SHM.
mg N = mω2
where x is the distance from maen position for block to leave contact N = 0
⇒ mg = mω2x ⇒ x =
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