Sound WavesHard
Question
If a simple pendulum oscillates with an amplitude of 50mm and time period of 2 sec then its maximum velocity is :
Options
A.0.6 m/s
B.0.16 m/s
C.0.8 m/s
D.0.32 m/s
Solution
v = ω 
; ehen u =0, v = vmax.
So, vmax = ωa
[where ω is angular velocity and a is amplitude]
vmax. =
= 0.16 m/sec
; ehen u =0, v = vmax.So, vmax = ωa
[where ω is angular velocity and a is amplitude]
vmax. =
= 0.16 m/secCreate a free account to view solution
View Solution FreeMore Sound Waves Questions
A source is moving with constant speed vs = 20 m/sec towards a stationary observer due east of source. Wind is blowing a...The particle displacement of a travelling longitudinal wave is represented by S = S (x, t). The midpoints of a compressi...A standing wave having 3 nodes and 2 antinodes is formed between 1.21 A distance then the wavelength is : -...Two vibrating tuning forks produce progressive waves given by y1=4 sin(500πt) andy2 = 2 sin(506πt). These tuning forks a...Three simple harmonic waves, identical in frequency n and amplitude A moving in the same direction are superimposed in a...