SHMMedium
Question
If a simple pendulum oscillates with an amplitude of 50mm and time period of 2 sec then its maximum velocity is :
Options
A.0.6 m/s
B.0.16 m/s
C.0.8 m/s
D.0.32 m/s
Solution
v = ω 
; ehen u =0, v = vmax.
So, vmax = ωa
[where ω is angular velocity and a is amplitude]
vmax. =
= 0.16 m/sec
; ehen u =0, v = vmax.So, vmax = ωa
[where ω is angular velocity and a is amplitude]
vmax. =
= 0.16 m/secCreate a free account to view solution
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