Properties of matterMedium
Question
A soap bubble in vacuum has a radius 3cm and another soap bubble in vacuum has radius 4cn. If two bubbles coalesce under isothermal condition. Then the radius of the new bubble will be:
Options
A.7 cm
B.5 cm
C.4.5 cm
D.2.3 cm
Solution
If r1, r2, r be radius of soap bubbles before and after the coalesec & r1, r2, and p the pressure then, applying gas laws equation
p1V1 + p2V2 = pV
r12 + r22 = r2
32 + 42 = r2 ⇒ =
= 5 cm
p1V1 + p2V2 = pV
r12 + r22 = r2
32 + 42 = r2 ⇒ =
= 5 cmCreate a free account to view solution
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