Momentum and CollisionHard

Question

For the given uniform square lamina ABCD, whose centre is O,
     

Options

A.IAC = √2IEF
B.√2IAC = 3IEF
C.IAD = 3IEF
D.IAC = IEF

Solution

       
By the theorem of perpendicular axes,
Iz = Ix + Iy or, Iz = 2 Iy
(∴   Ix = Iy by symmetry of the figure)
∴     IEF =         .....(i)
IZ = IAC + IBD = 2IAC
∴ IAC = IBD by symmetry of the figure
IAC =         ......(ii)
From (i)and (ii), we get IEF = IAC

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