Momentum and CollisionMedium
Question
A 150g tennis ball coming at a speed of 40m/s is hit straight back by a bat to a speed of 60m/s. The magnitude of the average force F on the ball, when it is in contect for 5 ms, is:
Options
A.2500N
B.3000N
C.3500N
D.4000N
Solution
The change in momentum
ᐃp = m(vf - vi)
= 0.150(60 - (-40))
= 0.150 × 100 = 15Ns
Thus, F =
= 3 × 103N
ᐃp = m(vf - vi)
= 0.150(60 - (-40))
= 0.150 × 100 = 15Ns
Thus, F =
= 3 × 103NCreate a free account to view solution
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