Geometrical OpticsHard
Question
A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in sucha way that its end closer to the pole is 20 cm away for the mirror. The length of the image is
Options
A.5 cm
B.10 cm
C.15 cm
D.2.5 cm
Solution
v1 = - 20cm ; u2 = - 10 cm
v5 = - 15 cmSimilarly v1 = - 20 cm
Length of image is V2 - V1 = 5 cm
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