Geometrical OpticsHard

Question

A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in sucha way that its end closer to the pole is 20 cm away for the mirror. The length of the image is

Options

A.5 cm
B.10 cm
C.15 cm
D.2.5 cm

Solution


                 
v1 = - 20cm ; u2 = - 10 cm
v5 = - 15 cm
Similarly v1 = - 20 cm
Length of image is V2 - V1 = 5 cm

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