ElectrostaticsHard
Question
Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 × 10-2 C and 5 × 10-2 C,respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is
Options
A.1 × 10-2 C
B.2 × 10-2 C
C.3 × 10-2 C
D.4 × 10-2 C
Solution
Common potential 
Change on bigger sphere is Q21 = C2V

C14πε0R1
C24πε0R2

(5 - 1) × 10-2
× 4 × 10-2 = 3 × 10-2 C

Change on bigger sphere is Q21 = C2V

C14πε0R1
C24πε0R2

(5 - 1) × 10-2
× 4 × 10-2 = 3 × 10-2 CCreate a free account to view solution
View Solution FreeMore Electrostatics Questions
As shown in figure four charges are placed at the corners of a square. If the side of square is 5 cm in length and the v...Assume a piece of cloud has area 25 × 106 m2 and electric potential 105V. If the height of cloud is 0.75 km, then e...A bullet of mass m and charge q is fired towards a solid uniformly charged sphere of radius R and total charge +q. If it...A solid sphere of radius R has a volume charge density ρ = ρ0 r2 ( Where ρ0 is a constant and ρ0 is ...The maximum electric field intensity on the axis of a uniformly charged ring of charge q and radius R will be :...