Set, Relation and FunctionMedium
Question
If w = α + iβ, where β ≠ 0 and z ≠ 1, satisfies the condition that 
is purely real, then the set of values of z is
is purely real, then the set of values of z is Options
A.{z : |z| = 1}
B.{z : z = 
}
}C.{z : z ≠ 1}
D.{z : |z| = 1, z ≠ 1}
Solution
⇒ (z
- 1)(
- w) = 0⇒ z
= 1 ⇒ |z|2 = 1 ⇒ |z| = 1.Create a free account to view solution
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