Trigonometric EquationHard
Question
If 0 < θ < 2π, then the intervals of values of θ for which 2 sin2θ - 5 sin θ + 2 > 0, is
Options
A.
B.
C.
D.
Solution
2sin2θ - 5 sinθ + 2 > 0
⇒ (sin θ - 2)(2 sinθ - 1) > 0
⇒ sin θ <
⇒ θ ∈
.
⇒ (sin θ - 2)(2 sinθ - 1) > 0
⇒ sin θ <
⇒ θ ∈
.Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
If f(x) = 2tan-1x + sin-1 , x > 1, then f(5) is equal to...The solution set of (5 + 4 cos θ) (2 cos θ + 1) = 0 in the interval [0, 2π] is :...If f(x) = (2x - π)3 + 2x - cosx, then (f-1 (x)) at x = π is equal to -...Locus of mid point of the portion between the axes of x cos α + y sin α = p where p is constant is...The equation of the normal to the curve y = x + sin x cos x at x = π/2 is-...