Trigonometric EquationHard
Question
If 0 < θ < 2π, then the intervals of values of θ for which 2 sin2θ - 5 sin θ + 2 > 0, is
Options
A.
B.
C.
D.
Solution
2sin2θ - 5 sinθ + 2 > 0
⇒ (sin θ - 2)(2 sinθ - 1) > 0
⇒ sin θ <
⇒ θ ∈
.
⇒ (sin θ - 2)(2 sinθ - 1) > 0
⇒ sin θ <
⇒ θ ∈
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