SolutionMedium
Question
Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H2 gas at the cathode is (1 Faraday = 96500 C mol-1)
Options
A.9.65 × 104 sec
B.19.3 × 104 sec
C.28.95 × 104 sec
D.38.6 × 104 sec
Solution
Q = i × t
Q = 10 × 10-3 × t
2H2O + 2e- → H2 + 2OH-
To liberate 0.01 mole of H2, 0.02 Faraday charge is required
Q = 0.02 × 96500 C
∴ 0.02 × 96500 = 10-2 × t
t = 19.30 × 104 sec
Q = 10 × 10-3 × t
2H2O + 2e- → H2 + 2OH-
To liberate 0.01 mole of H2, 0.02 Faraday charge is required
Q = 0.02 × 96500 C
∴ 0.02 × 96500 = 10-2 × t
t = 19.30 × 104 sec
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