SolutionHard
Question
Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H2 gas at the cathode is (1 Faraday = 96500 C mol-1)
Options
A.9.65 × 104 sec
B.19.3 × 104 sec
C.28.95 × 104 sec
D.38.6 × 104 sec
Solution
Q = i × t
Q = 10 × 10-3 × t
2H2O + 2e- → H2 + 2OH-
To liberate 0.01 mole of H2, 0.02 Faraday charge is required
Q = 0.02 × 96500 C
∴ 0.02 × 96500 = 10-2 × t
t = 19.30 × 104 sec
Q = 10 × 10-3 × t
2H2O + 2e- → H2 + 2OH-
To liberate 0.01 mole of H2, 0.02 Faraday charge is required
Q = 0.02 × 96500 C
∴ 0.02 × 96500 = 10-2 × t
t = 19.30 × 104 sec
Create a free account to view solution
View Solution FreeMore Solution Questions
An aqueous solution of a salt X turns blood red on treatment with SCN− and blue on treatment with K4[Fe(CN)6]. X a...Which of the following compound does not give test of sulphate ion in aqueous solution :-...Liquids A and B form an ideal solution. A certain solution of A and B contains 25 mole percent of A, whereas the vapours...Which of the following forms ideal solution ?...Which of the following solution will show minimum osmotic effect?...