SolutionHard
Question
Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H2 gas at the cathode is (1 Faraday = 96500 C mol-1)
Options
A.9.65 × 104 sec
B.19.3 × 104 sec
C.28.95 × 104 sec
D.38.6 × 104 sec
Solution
Q = i × t
Q = 10 × 10-3 × t
2H2O + 2e- → H2 + 2OH-
To liberate 0.01 mole of H2, 0.02 Faraday charge is required
Q = 0.02 × 96500 C
∴ 0.02 × 96500 = 10-2 × t
t = 19.30 × 104 sec
Q = 10 × 10-3 × t
2H2O + 2e- → H2 + 2OH-
To liberate 0.01 mole of H2, 0.02 Faraday charge is required
Q = 0.02 × 96500 C
∴ 0.02 × 96500 = 10-2 × t
t = 19.30 × 104 sec
Create a free account to view solution
View Solution FreeMore Solution Questions
A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the...A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct r...For 1 molal aqueous solution of the following compounds, which one will show the highest freezing point ?...Fog is a colloidal solution of:...A current of 2.6 ampere was passed through CuSO4 solution for 380 sec. The amount of Cu deposited is (at. wt. of Cu = 63...