Physics miscellaneousMedium
Question
A glass tube of uniform internal radius (r) has a valve separating the two identical ends. Initially, the valve is in a tightly closed position. End 1 has a hemispherical soap bubble of radius r. End 2 has sub-hemispherical soap bubble as shown in figure. Just after opening the valve,
Figure:
Figure:
Options
A.air from end 1 flows towards end 2. No change in the volume of the soap bubbles
B.air from end 1 flows towards end 2. Volume of the soap bubble at end 1 decreases
C.no changes occurs
D.air from end 2 flows towards end 1. volume of the soap bubble at end 1 increases
Solution
P1 = pressure just inside the bubble at the end 2 = P0 + 
P2 = pressure just inside the bubble at the end 1 = P0 +
R > r ⇒ P2 < P1 ⇒ Air will flow from end 1 to end 2
P2 = pressure just inside the bubble at the end 1 = P0 +
R > r ⇒ P2 < P1 ⇒ Air will flow from end 1 to end 2
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