EllipseHard
Question
The normal at a point P on the ellipse x2 + 4y2 = 16 meets the x-axis at Q. If M is the mid point of the line segment PQ, then the locus of M intersects the latus rectums of the given ellipse at the points
Options
A.

B.

C.

D.

Solution

Normal is 4x sec φ - 2y cosec φ = 12
Q ≡ (3 cos φ, 0)
M ≡ (α, β)
α =
cos φ ⇒ cos φ =
αβ = sin φ
cos2φ + sin2 φ = 1
⇒
α2 + β2 = 1 ⇒
x2 + y2 = 1 ⇒ latus rectum x = ± 2√3
+ y2 = 1 ⇒ y = ±
(± 2√3, ± 1/7).
Create a free account to view solution
View Solution FreeMore Ellipse Questions
Eccentricity of the ellipse 4x2 + y2 − 8x + 2y + 1 = 0 is-...The curve represented by x = 3 (cost + sin t), y = 4 (cost - sin t), is -...Maximum length of chord of the ellipse = 1, such that eccentric angles of its extremities differ by is -...The locus of the point of intersection of mutually perpendicular tangent to the ellipse = 1, is-...If the straight line y = 4x + c is a tangent to the ellipse = 1, then c will be equal to-...