FrictionHard
Question
A block of base 10 cm × 10 cm and height 15 cm is kept on an inclined plane. The coefficient of friction between them is √3. The inclination θ of this inclined plane from the horizontal plane is gradually increased from 0o. Then
Options
A.at θ = 30o, the block will start sliding down the plane
B.the block will remain at rest on the plane up to certain θ and then it will topple
C.at θ = 60o, the block will start sliding down the plane and continue to do so at higher angles
D.at θ = 60o, the block will start sliding down the plane and on further increasing θ, it will topple at certain θ
Solution
F.B.D. at just toppling condition.
For sliding, tan θ ≥ √3 ( = 1.732)
For toppling, tan θ ≥
( = 0.67)Create a free account to view solution
View Solution FreeMore Friction Questions
A solid sphere, a hallow sphere and a ring are released from top of an inclined plane (frictionless) so that they slide ...A uniform chain has mass M and length L. If is placed on a frictionless table with length l0 hanging over the edge. The ...Figure shows a block kept on a rough inclined plane. The maximum external force down the incline for which the block rem...A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. then the coeffic...The coefficient of friction between the block and the horizontal surface is μ as shown in figure. The block moves t...