Rotational MotionMedium
Question
A block of base 10 cm × 10 cm and height 15 cm is kept on an inclined plane. The coefficient of friction between them is √3. The inclination θ of this inclined plane from the horizontal plane is gradually increased from 0o. Then
Options
A.at θ = 30o, the block will start sliding down the plane
B.the block will remain at rest on the plane up to certain θ and then it will topple
C.at θ = 60o, the block will start sliding down the plane and continue to do so at higher angles
D.at θ = 60o, the block will start sliding down the plane and on further increasing θ, it will topple at certain θ
Solution
F.B.D. at just toppling condition.
For sliding, tan θ ≥ √3 ( = 1.732)
For toppling, tan θ ≥
( = 0.67)Create a free account to view solution
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