Complex NumbersHard
Question
Let z = cosθ + i sin θ Then the value of 
Im(z2m-1) at θ = 2o is
Im(z2m-1) at θ = 2o is Options
A.
B.
C.
D.
Solution
X = sinθ + sin3θ + .... + sin29θ
2(sinθ)X = 1 - cos2 θ + cos2 θ - cos4 θ + .... + cos28 θ - cos 30 θ
X =
2(sinθ)X = 1 - cos2 θ + cos2 θ - cos4 θ + .... + cos28 θ - cos 30 θ
X =
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