Quadratic EquationHard

Question

If a > 0 discriminant of ax² + 2bx + c is - ve, then is

Options

A.+ ve

B.(ac - b²) (ax² + 2bx + c)

C.- ve

D.0

Solution

We have By R₃ → R₃ - (xR₁ + R₂) =
= (ax² + 2bx + c) (b² - ac) = (+) (-) = - ve

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