Quadratic EquationHard
Question
If a > 0 discriminant of ax2 + 2bx + c is - ve, then
is
is Options
A.+ ve
B.(ac - b2) (ax2 + 2bx + c)
C.- ve
D.0
Solution
We have By R3 → R3 - (xR1 + R2) = 
= (ax2 + 2bx + c) (b2 - ac) = (+) (-) = - ve
By R3 → R3 - (xR1 + R2) = = (ax2 + 2bx + c) (b2 - ac) = (+) (-) = - ve
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