Atomic StructureHard
Question
The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is
Options
A.0
B.2.84
C.4.90
D.5.92
Solution
[Cr(CO)6]
Cr(24) = [Ar]3d5 4s1
Since (CO) is strong ligand, in Cr(CO)6 no unpaired electron is present. So ′spin only′ magnetic moment is zero.
Cr(24) = [Ar]3d5 4s1
Since (CO) is strong ligand, in Cr(CO)6 no unpaired electron is present. So ′spin only′ magnetic moment is zero.
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
When β-particles are sent through a tin metal foil, most of them go straight through the foil as...Which of the following is not a permissible value of angular momentum of electron in H-atom?...The mass of a particle is 10–10 g and its diameter is 10−4 cm. If its speed is 10–6 cm/s with 0.0001% uncertainty in mea...When photons of energy 4.25 eV strikes the surface of a metal ‘A’, the ejected photoelectrons have maximum kinetic energ...If n = 6, the correct sequence for filling of electrons will be...