Atomic StructureMedium
Question
The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is
Options
A.0
B.2.84
C.4.90
D.5.92
Solution
[Cr(CO)6]
Cr(24) = [Ar]3d5 4s1
Since (CO) is strong ligand, in Cr(CO)6 no unpaired electron is present. So ′spin only′ magnetic moment is zero.
Cr(24) = [Ar]3d5 4s1
Since (CO) is strong ligand, in Cr(CO)6 no unpaired electron is present. So ′spin only′ magnetic moment is zero.
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