Basic Maths and Units and DimensionsHard
Question
Two forces are such that the sum of their magnitudes is 18 N and their resultant is 12 N which is perpendicular to the smaller force. Then the magnitudes of the forces are
Options
A.12 N, 6 N
B.13 N, 5 N
C.10 N, 8 N
D.16 N, 2 N
Solution
Use tan α = 
⇒ tan 90o = = ∞ ∴ Q + P cos θ = 0 ⇒ P cos θ = - Q
144 = (P + Q) (P - Q) or P - Q = 144/18 = 8
∴ P = 13 N and Q = 5 N
⇒ tan 90o = = ∞ ∴ Q + P cos θ = 0 ⇒ P cos θ = - Q 144 = (P + Q) (P - Q) or P - Q = 144/18 = 8
∴ P = 13 N and Q = 5 N
Create a free account to view solution
View Solution FreeTopic: Basic Maths and Units and Dimensions·Practice all Basic Maths and Units and Dimensions questions
More Basic Maths and Units and Dimensions Questions
If energy E, velocity (V) and time (T) are choosen as the fundamental quantities, then the dimensions of surface tension...The angle of minimum deviation for a prism is 40o and the angle of the prism is 60o. The angle of incidence in this posi...An ideal gas is expanding such that PT2 = constant. The coefficient of volume expansion of the gas is:...Two wires are made of the same material and have the same volume. The first wire has cross-sectional area A and the seco...A stationary swimmer S inside a liquid of refractive index μ1 is at a distance d from a fixed point P inside the li...