Laws of MotionEasy
Question
When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed then the acceleration of the particle is
Options
A.F1/m
B.F2F3/mF1
C.(F2 - F3)/m
D.F2/m
Solution
Resultant of F2 and F3 is of magnitude F1.
Here only magnitude required else direction will be reverse of the F1
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the accelerat...A 5 kg. mass is accelerated from rest to 60 m/s in 1 sec. What force acts on it : -...Two masses m and M are attached with strings as shown. For the system to be in equilibrium we have...A block B of mass 0.6 kg slides down the smooth face PR of a wedge A of mass 1.7 kg which can move freely on a smooth ho...A particle moves in the X-Y plane under the influence of a force such that its linear momentum is (t) = A[cos(kt) - sin(...