Trigonometric EquationHard
Question
If the equation of the locus of a point equidistant from the points (a1, b1) and (a2, b2) is (a1 - a2) x + (b1 - b2) y + c = 0, then the value of ′c′ is
Options
A.
(a22 + b22 - a12 - b12)
(a22 + b22 - a12 - b12)B.a12 + a22 + b12 - b22
C. (a12 + a22 - b12 - b22)
(a12 + a22 - b12 - b22)D.
Solution
Let p(x, y)
(x - a1)2 + (y - b1)2 = (x - a2)2 + (y - b2)2
(a1 - a2) x + (b1 - b2) y +
(b22 - b12 + a22 - a12) = 0.
Hence, (A) is the correct answer.
(x - a1)2 + (y - b1)2 = (x - a2)2 + (y - b2)2
(a1 - a2) x + (b1 - b2) y +
(b22 - b12 + a22 - a12) = 0.Hence, (A) is the correct answer.
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