Properties of TriangleEasy
Question
Let z1 and z2 be two roots of the equation z2 + az + b = 0, z being complex. Further, assume that the origin, z1 and z2 form an equilateral triangle, then
Options
A.a2 = b
B.a2 = 2b
C.a2 = 3b
D.a2 = 4b
Solution
z12 + z22 - z1z2 = 0
(z1 + z2)2 - 3z1z2 = 0
a2 =3b .
Hence, (C) is the correct answer.
(z1 + z2)2 - 3z1z2 = 0
a2 =3b .
Hence, (C) is the correct answer.
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