Properties of TriangleHard
Question
Let z1 and z2 be two roots of the equation z2 + az + b = 0, z being complex. Further, assume that the origin, z1 and z2 form an equilateral triangle, then
Options
A.a2 = b
B.a2 = 2b
C.a2 = 3b
D.a2 = 4b
Solution
z12 + z22 - z1z2 = 0
(z1 + z2)2 - 3z1z2 = 0
a2 =3b .
Hence, (C) is the correct answer.
(z1 + z2)2 - 3z1z2 = 0
a2 =3b .
Hence, (C) is the correct answer.
Create a free account to view solution
View Solution FreeMore Properties of Triangle Questions
In a ᐃABC, if r = r2 + r3 − r1, and ∠A > then the range of is equal to -...Let PS be the median of the triangle with vertices P(2, 2), Q(6, - 1) and R (7, 3). The equation of the line passing thr...Let ᐃPQR be a triangle. Let and . If || = 12, ||= 4√3 and . = 24 then which of the following is (are) true ?...In a ᐃABC, 2R2 sinA sinB sinC =...If λ be the perimeter of the ᐃABC then b cos2 + c cos2 is equal to -...