Set, Relation and FunctionHard
Question
A velocity 
m/s is resolved into two components along OA and OB making angles 30o and 45o respectively with the given velocity. Then the component along OB is
m/s is resolved into two components along OA and OB making angles 30o and 45o respectively with the given velocity. Then the component along OB isOptions
A.
m/s
m/sB.(√3 - 1)m/s
(√3 - 1)m/sC.m/s
m/sD.(√3 - √2)m/s
(√3 - √2)m/s
(√6 - √2) m/s.More Set, Relation and Function Questions
Let R be a relation on the set N of natural numbers defined by nRm ⇔ n is a factor of m (i.e. n | m). Then R is -...Given the sets A = {1,2,3}, B = {3,4}, C = {4,5,6}, then is -...If A denotes the area between the curve 2{y} = [x] + 1 for 0 ≤ y 2 - x ≤ 0, then A is less than or equal to ...The relation R in the R of real numbers; defined as R = {(a, b) : a ≤ b2} then R is...If the two roots of the equation, (a − 1)(x4 + x2 + 1) + (a + 1)(x2 + x + 1)2 = 0 are real and distinct, then the ...