Straight LineHard
Question
If the straight lines x = 1 + s, y = - 3 - λs, z = 1 + λs and x = 
, y = 1 + t, z = 2 - t with parameters s and t respectively, are co-planar then λ equals
, y = 1 + t, z = 2 - t with parameters s and t respectively, are co-planar then λ equalsOptions
A.- 2
B.- 1
C.
D.0
Solution
Given lines 
= s and 
= t are coplanar then plan passing through these lines has normal perpendicular to these lines
⇒ a - bλ + cλ = 0 and
+ b - c = 0 (where a, b, c are direction ratios of the normal to the plan)
On solving, we get λ = - 2.
= s and = t are coplanar then plan passing through these lines has normal perpendicular to these lines ⇒ a - bλ + cλ = 0 and
+ b - c = 0 (where a, b, c are direction ratios of the normal to the plan) On solving, we get λ = - 2.
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