Trigonometric EquationHard
Question
Let A and B be two events such thatP
and P
where
stands for complement of event A. Then events A and B are
and P
where
stands for complement of event A. Then events A and B areOptions
A.equally likely and mutually exclusive
B.equally likely but not independent
C.independent but not equally likely
D.mutually exclusive and independent
Solution
and
⇒ P(A ∪ B) = 5/6 P(A) = 3/4
Also P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
⇒ P(B) = 5/6 - 3/4 + 1/4 = 1/3
P(A) P(B) = 3/4 - 1/3 = 1/4 = P(A ∩ B)
Hence A and B are independent but not equally likely.
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
Let α, β be such that π and cos α + cos β = , then the value of cos is...Let A be the area of triangle formed by any tangent to the curve xy = 4cosec2θ, θ ≠ nπ, n ∈ I...Locus of |z - cosθ - icosθ|+|z - sinθ + isinθ| = √2(where θ is constant, i =√-1 and...The general value of θ satisfying sin2 θ + sin = 2 is -...Let n be a positive integer such that sin + cos = . Then :...