Math miscellaneousHard

Question

If x = y (log y - log x + 1), then the solution of the equation is

Options

A.log = cx
B.x log = cy
C.log = cx
D.log = cy

Solution

= y(log y - log x + 1)

Put y = vx

⇒   v + = (log v + 1)
= v log v
⇒  
put log v = z
dv = dz
⇒  
ln z = ln x + ln c
z = cx
log v = cx
log = cx

Create a free account to view solution

View Solution Free
Topic: Math miscellaneous·Practice all Math miscellaneous questions

More Math miscellaneous Questions

If I = & B = then (I + B)50 is:-...Number of solution(s) of the equation = 8 in θ ∈[0, π] is...Let f(x) = for n ≥ 2 and g(x) = (x). Then ∫xn-2g(x)dx equals...z and w are two non zero complex no.s such that |z| = |w| and Arg z + Arg w = π then z equals...Let f(x) = If f(x) is continuous in, then f is...