Progression (Sequence and Series)Easy
Question
If in a frequently distribution, the mean and median are 21 and 22 respectively, then its mode is approximately
Options
A.22.0
B.20.5
C.25.5
D.24.0
Solution
Mode + 2Mean = 3 Median
⇒ Mode = 3 × 22 - 2 × 21 = 66 - 42 = 24.
⇒ Mode = 3 × 22 - 2 × 21 = 66 - 42 = 24.
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