Height and DistanceEasy
Question
A particle just clears a wall of height b at distance a and strikes the ground at a distance c from the point of projection. The angle of projection is
Options
A.tan-1
B.45o
C.tan-1
D.tan-1
Solution
a = (u cosα)t and b = (u sinα)t - 
gt2
b = a tan α -
also, c =
b = a tanα -
sec2 α
b = a tanα -
2tan α
⇒
tan α = b
tan α =
.
gt2 b = a tan α -
also, c =
b = a tanα -
sec2 α b = a tanα -
2tan α ⇒
tan α = btan α =
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