Math miscellaneousHard
Question
A body weighing 13 kg is suspended by two strings 5 m and 12 m long, their other ends being fastened to the extremities of a rod 13 m long. If the rod be so held that the body hangs immediately below the middle point. The tensions in the strings are
Options
A.12 kg and 13 kg
B.5 kg and 5 kg
C.5 kg and 12 kg
D.5 kg and 13 kg
Solution

T2 cos
= T1 cos θ ⇒ T1 cos θ = T2 sin θT1 sin θ + T2 cos θ = 13.
∵ OC = CA = CB
⇒ ∠AOC = ∠OAC and ∠COB = ∠OBC
∴ sin θ = sin A =
and cos θ =
⇒
⇒ T1 =
T2 T2
= 13T2
= 13T2 = 12 kgs. ⇒ T1 = 5 kgs.
Create a free account to view solution
View Solution FreeMore Math miscellaneous Questions
Let f be differentiable for all x. If f(1) = - 2 and f′(x) ≥ 2 for x ∈ [1, 6], then...If the expansion in powers of x is a0 + a1x + a2x2 + aa3x3 + ...., then an is...If α + iβ = (√3 + i)3n1(1 - i)-2n2, then...If a, b, c are in A.P., b, c, d are in G.P. & c, d, e are in H.P., then -...Let I = Then which one of the following is true?...