Redox and Equivalent ConceptHard

Question

Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statements is incorrect for this reaction?

Options

A.Cu2I2 is reduced
B.Evolved I2 is reduced
C.Na2S2O3 is oxidized
D.CuI2 is formed

Solution

2 CuSO4 + 4KI (excess) → 2K2SO4 + Cu2I2 + I2 ↑
Na2S2O3 + I2 → Na2S4O6 + 2NaI

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