ElectroMagnetic InductionHardBloom L3
Question
When the current changes from + 2 A to - 2 A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is
Options
A.0.2 H
B.0.4 H
C.0.8 H
D.0.1 H
Solution
If e is the induced e.m.f. in the coil, then e = - L 
Therefore, L = -
Substituting values, we get L =
= 0.1 H
Therefore, L = -
Substituting values, we get L =
= 0.1 HCreate a free account to view solution
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