ElectroMagnetic InductionHard
Question
When the current changes from + 2 A to - 2 A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is
Options
A.0.2 H
B.0.4 H
C.0.8 H
D.0.1 H
Solution
If e is the induced e.m.f. in the coil, then e = - L 
Therefore, L = -
Substituting values, we get L =
= 0.1 H
Therefore, L = -
Substituting values, we get L =
= 0.1 HCreate a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
A square coil of 0.01 m2 area is placed perpendicular to the uniform magnetic field of 103 weber/metre2. The magnetic fl...Soft iron is used to make the core of transformer, because of its :...An induction coil stores 32 joules of magnetic energy and dissipates energy as heat at the rate of 320 watts. when a cur...A very small circular loop of area 5 × 10-4 m2 and resistance 2 ohm is initially concentric and coplanar with a sta...A coil having 500 square turns each of side 10 cm is placed normal to a magnetic field which increased at a rate of 1.0 ...